Question: R(9) + 2T (9) = 2X (9) + Z(9) The reaction mixture represented above is at equilibrium at 298 K. The value of the equilibrium

R(9) + 2T (9) = 2X (9) + Z(9) The reaction

R(9) + 2T (9) = 2X (9) + Z(9) The reaction mixture represented above is at equilibrium at 298 K. The value of the equilibrium constant for the reaction is 16 at 298 K. If R(9), X (9) and Z (g) each have an equilibrium concentration of 2.0 M, what is the equilibrium concentration of T (g)

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