Question: reate your initial post by clicking on the Week 9 Discussion link to enter the forum and clicking on Create Thread when you are in
reate your initial post by clicking on the Week 9 Discussion link to enter the forum and clicking on Create Thread when you are in the forum.
Part 1: Introductory Information
The following shows the probability distribution for rolling a six-sided die and the Expected Value. The random variable in this case is the number showing when the rolling a six-sided die.
| 1 | ||
| 2 | ||
| 3 | ||
| 4 | ||
| 5 | ||
| 6 |
Therefore, the expected value of the random variable,x, is3.5.
Since the probability remains the same for each random variable,x, the probability distribution of thexis a uniform distribution.
Part 2: Your task
Step 1: Roll a six-sided die 40 times and record the results. Here are mine.
| 1 | 6 | 2 | 5 | 6 | 5 | 3 | 4 |
| 6 | 2 | 2 | 5 | 6 | 6 | 2 | 4 |
| 4 | 4 | 4 | 2 | 1 | 4 | 3 | 5 |
| 2 | 2 | 1 | 5 | 6 | 2 | 6 | 5 |
| 1 | 4 | 4 | 4 | 6 | 1 | 4 | 3 |
Step 2: Calculate the sample mean. Round to the nearest tenths place. Here is my result.
We now have a sample (n = 40) where the sample mean,(rounded to the nearest tenths place)
Step 3: Repeat steps 1 and 2 again and show your results.
| 6 | 6 | 2 | 1 | 6 | 5 | 3 | 5 |
| 2 | 6 | 5 | 2 | 3 | 1 | 6 | 1 |
| 2 | 2 | 6 | 1 | 5 | 5 | 1 | 2 |
| 3 | 5 | 5 | 4 | 3 | 3 | 1 | 5 |
| 1 | 2 | 1 | 6 | 4 | 2 | 1 | 6 |
Step 4: Find the mean of the two sample means.
mean of the sample means =
Step 4: Answer the following questions?
- Was the sample mean the same for both samples?
- Were the sample means close to each other?
- The mean is another term for expected value. How did your sample means compare to the expected value 3.5?
- How does the mean of your sample means (sampling distribution) compare to the expected value 3.5?
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