Recall that the linex=a

is a vertical asymptote of the graph ofyify

ory

asxa,

either from the right or from the left.

For the functiony= log₅(x3) +5

notice that asx3⁺,y.

Therefore, the vertical asymptote ofyisx=3

Before sketching the function, it will be helpful to find an expression forx, in terms ofy.

The function is

y= log₅(x3) +5.

This can also be written as follows.

(1) ________ = log₅(x3)

Now rewrite this equation in exponential form.

(2) _______ = x3

Isolate the variablex.

(3) _______ +3=x

(4) Now use the appropriate expression to calculate the missing values in this table. (Round your answer to five decimal places.)

x 3.00032 __________ 3.00800 3.04000 3.20000

y 0 1 2 3 ________

There are 5 blanks (2 in the table). Please answer all 5 blanks and make the answers clear.