Reduce this. K$=20$ and T infinity $=65$

Node: $T_{1,1},$ For all eqns, assume $x=y$ and his constant

Heat In

Heat out

$\frac{?}{\text{b}\text{a}\text{r}}(h{)}_c\frac{y}{2}(T_{}-T_{1,1})-\frac{{}_x}{2}(\frac{T_{10}-T_{2,1}}{y})+q_G^{}=-\frac{ky}{2}(\frac{T_1-T_{10}}{x})\frac{-}{b}ar(h{)}_c\frac{x}{2}(T_{}-T_{1,1})\frac{?}{b}$

$ar(h{)}_c(T_{}-T_{1\mathrm{.}1})-T_{1,1}+T_{2\mathrm{.}1}+q_G^{}=-T_{1,2}+T_{1,1}\frac{-}{b}ar(h{)}_c(T_{}-T_{1,1})$

$-h_c(T_{}-T_{1\mathrm{.}1}),-T_c(T_{},T_{1\mathrm{.}1})$

$-T_{1,1}+T_{2,1}+2q_G^{}=-T_{1,2}+T_{1,1}-T_c(2T_{}-2T_{1,1})$

$-T_{1,1}+T_{2,1}+T_{1,2}-T_{1,1}=-T_c(2T_{}-2T_{1,1})-2q_G^{}$

$-h_{0}2T_{11}-T_1+T_{2,1}+T_{1,2}-T_{11}=-h_{c}2T_{}-2i_2$

$-4T_{1,1}+T_{T_1}+T_{1,2}=\frac{\frac{-}{b}ar(h{)}_{c}2T_{}-\frac{2q_G^{}}{k}}{k}$

$\frac{h_c}{k}$