Refer to Exercise 19 and suppose X1. = 10, x = 15, and = 20. Can...
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Refer to Exercise 19 and suppose X1. = 10, x = 15, and = 20. Can you now find a value of SSE that produces such a contradiction between the F test and Tukey's procedure? Reference exercise 19 Consider a single-factor ANOVA experiment in which I = 3, J = 5, x. = 10, = 12, and x = 20. Find a value of SSE for which f> F05.2.12, so that Ho: u, = z = uz is rejected, yet when Tukey's procedure is applied none of the u's can be said to differ significantly from one another. 10, 1. %3D %3D Find a value of SsSE for which f> Fo5,2.12 so that Ho: = 2 = H3 is rejected, yet when Tukey's procedure is applied none of the p's can be said to differ significantly from one another. Refer to Exercise 19 and suppose X1. = 10, x = 15, and = 20. Can you now find a value of SSE that produces such a contradiction between the F test and Tukey's procedure? Reference exercise 19 Consider a single-factor ANOVA experiment in which I = 3, J = 5, x. = 10, = 12, and x = 20. Find a value of SSE for which f> F05.2.12, so that Ho: u, = z = uz is rejected, yet when Tukey's procedure is applied none of the u's can be said to differ significantly from one another. 10, 1. %3D %3D Find a value of SsSE for which f> Fo5,2.12 so that Ho: = 2 = H3 is rejected, yet when Tukey's procedure is applied none of the p's can be said to differ significantly from one another.
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Answer rating: 100% (QA)
It isgiven that I3 J5 1 10 x 12 and x 20 From the information we can obtain X I xJ Since I 10x5 50 S... View the full answer
Related Book For
Statistics for Business and Economics
ISBN: 978-0321826237
12th edition
Authors: James T. McClave, P. George Benson, Terry T Sincich
Posted Date:
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