Refer to Table 56.1 - Factors for Computing Control Chart Limits (3.sigma) for this problem. Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day 1 2 3 Meanx (mm) 1549 1552 1536 155.5 158.6 Range R (mm) 44 4.6 4.1 5 5.2 4.3 a) What is the value of x? 155,66 mm (round your response to two decimal places), b) What is the value of R? R$ 4.52 mm (round your response to two decimal places) c) What are the UCL and LCL, using 3.sigma? Upper Control Limit (UCL.:) 166.05 mm (round your response to two decimal placoa) Lower Control Limit (LC) 154,18 mm (round your response to two decimal places) d) What are the UCLR and LCR using 3-sigma? Upper Control Limit (UCL)- 8.05 mm (round your response to two decimal places) a) What is the value of x2 x= 155,56 mm (round your response to two decimal places) b) What is the value of R? R= 4.52 mm (round your response to two decimal places) c) What are the UCL and LCL, using 3-sigma? Upper Control Limit (UCL) - 156.95 mm (round your response to two decimal places) Lower Control Limit (LCL) = 154,18 mm (round your response to two decimal places) d) What are the UCLR and LCLA Using 3-ulama? Upper Control Limit (UCLR) 8.03 mm (round your response to two decimal plocoa). Lower Control Limit (LCR) 101 mm (round your response to two decimal places) ) If the true diameter mean should be 156 mm and you want this as your conter (nominal) lino, what are the new UCL, and LCL? Upper Control Limit (UCL) -mm (round your response to two decimal placea)