Repeat the problem we discussed in class, regarding the deflection along a simply supported beam. The deflection (v) in a simply supported beam with a uniform load q and a tensile axial load T is given by d'y Ty qx(L -x) where rlocation along the beam in) T- tension applied (Ibs E Young's modulus of elasticity of the beam (psi) I- second moment of area (in4) q-uniform loading intensity (Ib/in) L- length of beam (in) 4 Given, T = 7200 lbs, q : 5400 bin, L : 75 in, E-30x106 psi,120 4 Find the defection along the beam using the finite difference method along with the following requirements: 1. Use central difference for the 2nd derivative. 2. Use the true error of 1*10-3 as the stopping accuracy. Note: Evaluate the error in the middle of the beam. The exact solution is provided below. + 3.75 10,-1.775656266 x10 e004142* -1.974343774 x10 e y = 0.375x2-28. 125x 5 e0.0014142x 5 0.0014142 x Output your result in column vector form [x, y (finite difference method), y (true value)] for all x. Repeat the problem we discussed in class, regarding the deflection along a simply supported beam. The deflection (v) in a simply supported beam with a uniform load q and a tensile axial load T is given by d'y Ty qx(L -x) where rlocation along the beam in) T- tension applied (Ibs E Young's modulus of elasticity of the beam (psi) I- second moment of area (in4) q-uniform loading intensity (Ib/in) L- length of beam (in) 4 Given, T = 7200 lbs, q : 5400 bin, L : 75 in, E-30x106 psi,120 4 Find the defection along the beam using the finite difference method along with the following requirements: 1. Use central difference for the 2nd derivative. 2. Use the true error of 1*10-3 as the stopping accuracy. Note: Evaluate the error in the middle of the beam. The exact solution is provided below. + 3.75 10,-1.775656266 x10 e004142* -1.974343774 x10 e y = 0.375x2-28. 125x 5 e0.0014142x 5 0.0014142 x Output your result in column vector form [x, y (finite difference method), y (true value)] for all x