Repeat the solution to Example $28\mathrm{.}2-1$ using two equal "doses" of fresh $)$ activated

carbon of $0\mathrm{.}70kg$ each. This process is two batch adsorption steps applied one after the

other. After the first batch adsorption step, all of the adsorbent is removed leaving the

same volume of solution, but at a lower equilibrium concentration. The solution

remaining is contacted again with another $0\mathrm{.}7kg$ of fresh activated carbon. This is a bit

tricky, so think it through very carefully. Again, use a spreadsheet calculation approach,

not graphical. Is the percent of the original phenol extracted the same as in part a$,$ or is it

higher?