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Required information

A steel tube $(E=200$GPa with a $32-mm$ outer diameter and a $4-$mm wall thickness is placed in a vise, which is adjusted so that its jaws just touch the ends of the tube without exerting pressure on them. The two forces shown are then applied to the tube. After these forces are applied, the vise is adjusted to decrease the distance between its jaws by $0\mathrm{.}2mm.$ It is given that $P=46kN.$

NOTE: This is a multi$-$part question. Once an answer is submitted, you will be unable to return to this part.

Determine the forces exerted by the vise on the tube at A and $D.$

The force exerted by the vise on the tube at $A$ is $kN.$

The force exerted by the vise on the tube at $D$ is kNlarr.