Question: RESET THE FORM GRAPH: f(x) = x^2-3x+2 Step1. Find the x-intercepts (if any). Solve: x^2-3x+2=0 This is a EQUATION. Note: X^2 = x2 a= b

RESET THE FORM GRAPH: f(x) = x^2-3x+2 Step1. Find the x-intercepts (if any). Solve: x^2-3x+2=0 This is a EQUATION. Note: X^2 = x2 a= b = C = A = The equation has S REAL SOLUTIONS. x1 =] and x2 = Step2. Find the y-intercept. x = and y = Step3. Find the vertex. xv =and yv = Step4. Find another point on the grapf of f. x =_and y = Step5. Is the parabola opening up or down?RESET THE FORM SOLVE: x^2+3x-4 0 NOTE: X^2 = x2 This is a INEQUALITY. Step 1: Find the x-intercepts 1+x^2 = 0 This is a EQUATION. a= b = C = A = The equation has REAL SOLUTIONS. x1 = and x2 = Step 2: Fill out the Table of Signs Table of Signs X -00 too Test Value X = y = 1+x^2 Step 3: Solution Choose from the following

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