Rod $\backslash ($ A B $\backslash )$ is held in place by the cord $\backslash ($ A C $\backslash ).$ Knowing that $\backslash ($ c$=820\backslash$mathrm$\{$~mm$\}\backslash )$ and that the moment about $\backslash ($ B $\backslash )$ of the force exerted by the cord is $810\backslash (\backslash$mathrm$\{$N$\}-\backslash$mathrm$\{$m$\}\backslash ),$ determine the tension in the cord by the three methods indicated.

a$)$ by applying the cable tension component at $\backslash ($ A $\backslash )$ perpendleular to rod $\backslash ($ A B $\backslash )$

Angle between horizontal and rod $\backslash ($ A B $\backslash )$

Angle between horizontal and cable $\backslash ($ A C $\backslash )$

Angle BAC

Length of $\backslash (\backslash$operatorname$\{$rod$\}$ A B$=\backslash )$ m

Tac $\backslash (=\backslash )$ Tension In Cable AC$.$

Component of Tac perpendicular to rod AB $=$ Tac$*($

Moment of Cable tenslon about pin $\backslash (\backslash$mathrm$\{$B$\}=\backslash )$ Tac$*$

N m clockwise

Tension in cable AC $=$ N

b$)$ by applying the cable tension at C

Angle between horizontal and cable $\backslash ($ A C $\backslash )$ as above.

Moment of Cable tension about pin $\backslash (\backslash$mathrm$\{$B$\}=\backslash )$ Tac$*$

$|$N m clockwise

The tension in the cord is

N $.$

c$)$ using horizontal$(\backslash ($ x $\backslash ))$ and vertical$(\backslash ($ y $\backslash ))$ components

Use negative numbers for left or down components.