Rod OA rotates counterclockwise at a constant angular rate $=4ra\frac{d}{s}.$ The double collar

$B$ is pin$-$connected together such that one collar slides over the rotating rod and the

other collar slides over the circular rod described by the equation $r=(1\mathrm{.}6cos)m.$ Collar

$B$ has a mass of $0\mathrm{.}4$ kg $.$ Motion is in the horizontal plane.

What is the force between the circular ring and the collar when $=30$ degrees? Solution

lies in $(-25,-15)$