Question: (RSA encryption) Let n = 5 . 17 = 85 be the modulus of a (very modest) RSA public key encryption and d = 5

(RSA encryption) Let n = 5 . 17 = 85 be the
(RSA encryption) Let n = 5 . 17 = 85 be the modulus of a (very modest) RSA public key encryption and d = 5 the decryption key. Since 85 is in between 25 and 2525, we can only encode one letter (with a two-digit representation) at a time. a) (10 pts) Use the decryption function M = Ca mod n = C$ mod 91 to decipher the 5 encrypted message 68 - 44 - 00 - 52 - 59

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