Question: Section 10.5: Problem 20 (1 point) Find the distance from the point Q = (5, -5, 5) to the plane -5x - 2y + 5z

 Section 10.5: Problem 20 (1 point) Find the distance from thepoint Q = (5, -5, 5) to the plane -5x - 2y+ 5z = 7.Section 10.5: Problem 17 (1 point) Find the angle

Section 10.5: Problem 20 (1 point) Find the distance from the point Q = (5, -5, 5) to the plane -5x - 2y + 5z = 7.Section 10.5: Problem 17 (1 point) Find the angle of intersection of the plane 321: 3y 2z = 3 with the plane 3/ 3:1: 52 = 3. Answer in radians: U and in degrees: D Section 10.5: Problem 19 (1 point) Find an equation of the plane consisting of all points that are equidistant from A(2, 3, 5) and B(1, 1, 3). C] Note: you have to enter the full equation

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