Question: Section 4 - 2: Conditional Probability Two Events with replacement 1. A bag contains 3 Red (R) marbles, 2 Blue (B) marbles and 1 Yellow(Y)

 Section 4 - 2: Conditional Probability Two Events with replacement 1.A bag contains 3 Red (R) marbles, 2 Blue (B) marbles and1 Yellow(Y) marbles. Find the following probabilities if you select 2 marbles,one at a time with replacement. State the answer as a decimalrounded to 2 decimal places. 3 R 3 R and 2 B2 B 1 Y then 1 Y 6 marbles with replacement 6marbles 1A. P( R and B ) = P( R and thenB ) = Fraction Fraction Decimal 1B. P( R and Y )= P( R and then Y ) = 1C. P( 2 Y) = P( Y and then Y) = 1D. P( B andR ) = P( B and then R ) = 1E. P(

G and Y ) = P( G and then Y ) =1F. P( 2 B ) = ( B and then B )= 1G. P( YIB ) = 1H. P( RIY ) = FractionDecimal Fraction Decimal 11. P( B IR ) = 1J. P( YIB) = Fraction Decimal Fraction DecimalTwo Events with replacement 2. A bagcontains 5 Red (R) marbles, 3 Blue (B) marbles and 2 Yellow(Y)marbles Find the following probabilities if you select 2 marbles, one ata time with replacement. State the answer as a decimal rounded to2 decimal places. 5 R and 5 R 3 B 3 B2 Y then 2 Y 10 marbles with replacement 10 marbles 2A.P( R and B ) = P( R and then B )

Section 4 - 2: Conditional Probability Two Events with replacement 1. A bag contains 3 Red (R) marbles, 2 Blue (B) marbles and 1 Yellow(Y) marbles. Find the following probabilities if you select 2 marbles, one at a time with replacement. State the answer as a decimal rounded to 2 decimal places. 3 R 3 R and 2 B 2 B 1 Y then 1 Y 6 marbles with replacement 6 marbles 1A. P( R and B ) = P( R and then B ) = Fraction Fraction Decimal 1B. P( R and Y ) = P( R and then Y ) = 1C. P( 2 Y ) = P( Y and then Y) = 1D. P( B and R ) = P( B and then R ) = 1E. P( G and Y ) = P( G and then Y ) = 1F. P( 2 B ) = ( B and then B ) = 1G. P( YIB ) = 1H. P( RIY ) = Fraction Decimal Fraction Decimal 11. P( B IR ) = 1J. P( YI B) = Fraction Decimal Fraction DecimalTwo Events with replacement 2. A bag contains 5 Red (R) marbles, 3 Blue (B) marbles and 2 Yellow(Y) marbles Find the following probabilities if you select 2 marbles, one at a time with replacement. State the answer as a decimal rounded to 2 decimal places. 5 R and 5 R 3 B 3 B 2 Y then 2 Y 10 marbles with replacement 10 marbles 2A. P( R and B ) = P( R and then B ) = Fraction Fraction Decimal 2B. P( R and Y ) = P( R and then Y ) = 2C. P( 2 Y ) = P( Y and then Y) = 2D. P( R and R ) = P( R and then R ) = 2E. P( G and Y ) = P( G and then Y ) = 2F. P( 2 B ) = ( B and then B ) = E 2G. P( YIB ) = 2H. P(RIY ) = Fraction Decimal Fraction Decimal 21. P( B IR ) = 2J. P( Y I B ) = Fraction Decimal Fraction Decimal Two Events with replacement3. A bag contains 4 Red (R) marbles, 3 Blue (B) marbles and 5 Yellow(Y) marbles. Find the following probabilities if you select 2 marbles, one at a time with replacement. State the answer as a decimal rounded to 2 decimal places. 4 R 4 R 3 B and 3 B 5 Y then 5 Y 12 marbles with replacement 12 marbles 3A. P( R and B ) = Fraction Fraction Decimal 3B. P( R and Y ) = 3C. P( B and Y ) = 3D. P( R and R ) = 3E. P( B and Y ) = 3F. P( 2 Y) = = 3G. P( G and Y ) = 3H. P( R I B ) = 31. P( G IR ) = Fraction Decimal Fraction Decimal Three Events with replacement4. A bag contains 2 Red (R) marbles, 3 Blue (B) marbles and 5 Yellow(Y) marbles Find the following probabilities if you select 3 marbles, one at a time with replacement. State the answer as a decimal rounded to 2 decimal places. 2 R 2 R 2 R and 3 B and 3 B 3 B then 5 Y then 5 Y 5 Y 10 marbles with replacement 10 marbles with replacement 10 marbles 4A. P( 3 B ) = Fraction Fraction Fraction Decimal 4B. P( 3R ) = 4C. P( 3Y ) = 4D. P( 3R ) = 4E. P( 3Y ) = 4F. P ( 3 R or Y ) = 4G. P( 2YI R ) = Decimal 4H. P( R1 2B ) = Fraction Decimal Two Events WITHOUT replacement 5. A bag contains 3 Red (R) marbles, 2 Blue (B) marbles and 1 Yellow(Y) marbles.Find the following probabilities if you select 2 marbles, one at a time without replacement. State the answer as a decimal rounded to 2 decimal places. 3 R and

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