see the attachment

I ran an Error Correction iviodeL obtaining the results depicted below. The model comes from the literature, where Dutch disease effects were tested in the case of Russia. My dependent variable was the real effective exchange rate. while oil prices (OI L_Prices:|1 terms of trade {TOT}. public deficit (G D'v'j, industrial productivity (PR) were independent variables. My main concern is that only the Error Correction Term] the dummy variable. and the intercept are statistically signicant. Moreover. residuals are not normally distributed. while also the residuals are heteroscedasdic. There is no serial co nelation issue according to the LM test. How can I improve my ndings? Thank you beforehand. 258 9 Models with self-selectivity where a = Cov( in , w) and of-) and (.) are. respectively, the density function and the distribution function of the standard normal. The mean income of fishermen is given by 2) 1-0(2) where op - Covtu, W). Because and 0zu we have ory 130. We can now consider different cases.4. (30 points) A statistics exam has five easy questions and three hard questions. You have six friends who are in the class, five are moderately prepared and one is very prepared. Probability Easy Questions Correct Probability Hard Questions Correct 5 Moderately Prepared Friends 80% Chance 66.666% (two-thirds) 1 Very Prepared Friend 95% 80% The probability of answering any one question correctly is completely independent of the probability of answering any other question correctly for every student. (a) What is the probability your very prepared friend gets all eight questions right? (b) What is the probability that a randomly chosen moderately prepared friend gets all eight of them correct? (c) The professor randomly chooses one exam to grade first. The exam happens to belong to one of your six friends and it happens to get all eight questions correct. What is the probability it is the exam of your one very prepared friend. (d) Let the random variable VP be the number of questions answered correctly by your very prepared friend. Find E[VP] (e) Let M1, Me, ..., Ms be the scores received by your five moderately prepared friends. Let D be the difference between the average score of your five moderately prepared friends and the score of your one very prepared friend: D = M1 + M2 + M3 + MA + M5 - VP 5 Find the variance of D (hint: Var(VP) = .7175 and Var(M;) = 1.4667)Linda Insurance Company Lid. is a resident insurance company carrying out both general and life assurance businesses. The following information relates to the insurance company's financial year ended 31 December 2007:Additional Information: Management expenses for Life assurance business include Sh_400,000 being salaries to pension department employees and Sh_456,000 for trust scheme rent. Investment income comprise