Select the correct scatterplot. 50 46 36 O 20 10 15 on 25 20 25 An As 50 5 50 46 30 O 20 10 50 40 30 O 20 10 The regression equation is y = X + Round to two decimal places if necessary.) For x = 2750, y = Round to two decimal places if necessary.) For x = 2050, y = (Round to two decimal places if necessary.) The mileage for the Select an answer ~ pounds is probably closer to the true mileage because it is interpolation, while the one for Select an answer ~ pounds is extrapolation.The weight of a car can influence the mileage that the car can obtain. A random sample of cars' weights and mileage was collected and are in the table. Create a scatter plot and find a regression equation between weight of cars and mileage. Then use the regression equation to find the mileage on a car that weighs 2750 pounds and on a car that weighs 2050 pounds. Which mileage that you calculated do you think is closer to the true mileage? Why? Weights and Mileages of Cars 7:43 & 228! LTE @) Done & myopenmath.com AA G O | oe!%3 [* AN AK N The regression equation is y" = -1.08 V| x+ 66.99 v| o (Round to two decimal places if necessary.) For x = 2750, y"=| 37.16 X (Round to two decimal places if necessary.) For x = 2050, yv"'=| 44.75 X (Round to two decimal places if necessary.) The mileage for the \\/ o pounds is probably closer to the true mileage because it is interpolation, while the one for (2050 )v o pounds is extrapolation. Question Help: & Message instructor Submit Question /\\ B