Select the FIRST correct reason from the list below that explains why the given series converges.

A$.$ Convergent geometric series

B$.$ Convergent p series

C$.$ Comparison $($or Limit Comparison$)$ with a geometric or $p$ series

D$.$ Alternating Series Test

E$.$ Cannot apply any test done so far in class

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{(-1{)}^{n}ln(e^n)}{n^{6}cos(n)}$

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{cos(n)}{ln(2n)}$

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{(24{)}^n}{(n+1)5^{2n}}$

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{3(6{)}^n}{9^{2n}}$

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{(-1{)}^n}{3n+6}$

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{n^2+\sqrt[\phantom{2}]{n}}{n^4-3}$