Question: Set up the ANOVA table. (Round your values for mean squares and F to two decimal places, and your p-values to three decimal places.) Test

 Set up the ANOVA table. (Round your values for mean squaresand F to two decimal places, and your p-values to three decimal

Set up the ANOVA table. (Round your values for mean squares and F to two decimal places, and your p-values to three decimal places.) Test for any significant main effects and any interaction effect. Use =0.05. Find the value of the test statistic for factor A. (Round your answer to two decimal places.) Find the p-value for factor A. (Round your answer to three decimal places.) p-value = State your conclusion about factor A. Because the p-value >=0.05, factor A is not significant. Because the p-value =0.05, factor A is not significant. Because the p-value >=0.05, factor A is significant. Because the p-value =0.05, factor A is significant. Find the value of the test statistic for factor B. (Round your answer to two decimal places.) Find the p-value for factor B. (Round your answer to three decimal places.) p-value = State your conclusion about factor B. Because the p-value >=0.05, factor B is not significant. Because the p-value >=0.05, factor B is significant. Because the p-value =0.05, factor B is not significant. Because the p-value =0.05, factor B is significant. Find the value of the test statistic for the interaction between factors A and B. (Round your answer to two decimal places.) Find the p-value for the interaction between factors A and B. (Round your answer to three decimal places.) p-value = State your conclusion about the interaction between factors A and B. Because the p-value =0.05, the interaction between factors A and B is not significant. Because the p-value >=0.05, the interaction between factors A and B is not significant. Because the p-value >=0.05, the interaction between factors A and B is significant. Because the p-value =0.05, the interaction between factors A and B is significant

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