Question: Set up the following circuit, which includes a 9 V battery, 10 $2 resistor, a 20 $2 resistor, and three wires: Voltage 6.00 V You

 Set up the following circuit, which includes a 9 V battery,

Set up the following circuit, which includes a 9 V battery, 10 $2 resistor, a 20 $2 resistor, and three wires: Voltage 6.00 V You can use the "voltmeter" to measure voltages across all of the elements (resistors, wires, etc.). 1. Describe in words what happens when you reverse the order of the black and red voltmeter probes. Do you think that this reflects anything about the circuit? 2. Measure the voltage across all clements; How does the battery voltage compare to the voltages of all of the other elements? You may have noticed that the voltages of all of the wires and resistors add up to the battery voltage. Energy is conserved in a circuit so all of the energy provided by the battery (voltage is energy per charge) is dissipated in the wires and resistors (as thermal energy, light energy (in lightbulbs), motional energy (in motors), etc). This is known as Kirchoff's Loop Rule: AV source = E AV (6) all other elements on the boop

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