short answer only please

(1 point) This question concerns block cipher modes. We will use a simple atine cipher, which can be expressed in C as follows. char cipheriunsigned char block, charkey) f. return (key+11'blocks?256, 3 Note that the block size is 8 bits, which is one byte (and one ASCil character). We wid work wath the fixed key ox08. We now enerypt vanous plaintexts using modes for this cipher in every case in which the mode requires an N, the IV wit be 0xAA. In the case of CiP mode. we use a (neoce II counter) arrangement in which the nonce is the left 5 bits of 0xAA and the counter is a 3 bit counter that begins at 0 . in all of the problems given below, one character is one block. Each character of the plaintext should be regarded as its corresponding Ascil code. 0) Encrypt the plaintext" forty using CTR mode. Please enter your answer in hex. (Please do "not" enter an 0x as this has been done.) 0x b) Enetypt the ptaintest "fifty using ECB mode. Please enter your answer in hex. 0x c) Encrypt the plainest " n iftyr using CFB mode. Plaese enter your answer in hex: Qx d) Encrvot the dlainlext "Hhirifty" using CBC mode. Please enter your answer in hex. 0x e) Encryet the plaitext "iniffty usng OFB mode. Please enter your answer in hex. DX