Show (by hand) how Haskell evaluates:

myOR[False, True, False]

given the code:

foldr:: (a -> b => b) => b -> [a] -> b foldr bf [] = b foldr bf (x:xs) = fx (foldr bf xs) = myOR:: [Bool] -> Bool myOR = foldr myor False myor:: Bool -> Bool -> Bool myor False False False myor True foldr:: (a -> b => b) => b -> [a] -> b foldr bf [] = b foldr bf (x:xs) = fx (foldr bf xs) = myOR:: [Bool] -> Bool myOR = foldr myor False myor:: Bool -> Bool -> Bool myor False False False myor True