Show that the Boolean function conjuction $x_2$ is not linearly separable $($i$.$e$.$ there is no linear classifier sign$(w_1{x}_1+w_2{x}_2+b)$ that classifies all $4$ possible input points correctly$).$ Assume that "true" is represented by $1$ and "false" is represented by $-1.$ Show that there is a linear separator for this Boolean function when we use the kernel $K(x,y)$conjuction$($x$.$y$)^2($x$.$y denotes the ordinary inner product$).$ Give the weights and the value of $b$ for one such separator.