Show that the function $y=f(x)$ is a solution of the differential equation.

$y=8e^{-x}$

$y^{\text{'}\text{'}}-y=0$

First, given $y=8e^{-x},$ we can find $y^{\text{'}\text{'}}.$

$y^{\text{'}\text{'}}=$

Now, substitute $y$ and $y^{\text{'}\text{'}}$ in the given differential equation and verify.

$y^{\text{'}\text{'}}-y=,-8e^{-x}=0$