Question: Show that the two dimensional space whose metric is ds=de-du (it is called 'Rindler space') is just two-dimensional Minkowski space ds=-df+d in disguise. Do


Show that the two dimensional space whose metric is ds=de-du (it is

Show that the two dimensional space whose metric is ds=de-du (it is called 'Rindler space') is just two-dimensional Minkowski space ds=-df+d in disguise. Do this by finding the appropriate change of coordinates z(u, v), t(u, v).

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