Show that there exists a bounded subinterval of (0,) on which log(x) is Lipschitz continuous.

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Show that there exists a bounded subinterval of (0,∞) on which log(x) is Lipschitz continuous.

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Show that there exists a bounded subinterval of (0,) on which log(x) is Lipschitz continuous.

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Given two metric spaces X dX and Y dY where dX denotes the metric on the set X and dY is the metric ... View the full answer

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