Simple pendulum Use these numbers for this problem: g=9.80 m/s2 The coefficient of linear thermal expansion for brass is 18.7 x 10-6 /C Note that this problem also allows us to do a bit of review regarding a simple pendulum. A particular clock uses a simple pendulum to keep time. The pendulum consists of a metal ball attached to a thin brass rod. The other end of the rod is attached to a support that allows the rod to swing freely back and forth. The rod is attached to the center of the ball, which allows us to use the length of the rod as the length of the simple pendulum. Note that it's a good idea to keep as many decimal places as you can when working through the problem, but you can round each answer off to three significant figures.@ Part (a) O Homework ' Answered ' Due Nov215t,5:30 PM The length ofthe brass rod is chosen such that when the temperature is 200C, the pendulum has a period of exactly 1.20 5. At that temperature, what is the length of the rod? m Type your numeric answer and submit 0.357 x/ You are correct Answered Correct! - 4 attempts left {I Resubmit @ Part (b) O Homework I Answered I Due Nov215t,5:30 PM On a particular hot summer day, the temperature ofthe clock is 29.0C, so the brass rod is longer than it is when the temperature is only 20.0\"C. What is the change in length experienced by the rod, expressed in micrometers? um Type your numeric answer and submit 60.7 K" Open in Reac You are correct Part (c) Homework . Answered . Due Nov 21st, 5:30 PM When the temperature rises and the rod gets longer, the period of the pendulum gets longer. This means the clock runs a little slow. If the clock runs at the higher temperature (the temperature specified in part (b)) for 24 hours, how many seconds slow will it be? S Type your numeric answer and submit 288 X You are incorrect Answered - Incorrect . 4 attempts left Rest k Open in