Question: Simplified the following Boolean Expressions: F = A'B'C' + AB'C' + ABC' + ABC F = A'B'C'D' + A'BC'D' + ABC'D' + AB'C'D' + A'BC'

Simplified the following Boolean Expressions:

F = A'B'C' + AB'C' + ABC' + ABC F = A'B'C'D' + A'BC'D' + ABC'D' + AB'C'D' + A'BC' D + ABC'D + AB'CD' + ABCD' F = A'B'C'D' + AB'C'D' + A'B'CD' + AB'CD' + A'BC'D + ABC'D + ABCD + A'BCD F = A'B'C' + A'BC' + ABC' + AB'C'+ A'BC F(A'B'C'D) = sigma m(3, 4, 5, 7, 9, 13, 14, 15)

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