Simulate the following program by converting each instruction to corresponding machine code. Then store the

machine code in memory starting from location $10$: module SIMCOMP $($clock$,$ PC$,$ IR$,$ MBR$,$ AC$,$ MAR$)$;

input clock;

output PC$,$ IR$,$ MBR$,$ AC$,$ MAR;

reg $[15$:$0]$ IR$,$ MBR$,$ AC;

reg $[11$:$0]$ PC$,$ MAR;

reg $[15$:$0]$ Memory $[0$:$63]$;

reg $[2$:$0]$ state;

parameter load $=4\text{'}$b$0011,$ store$=4\text{'}$b$1011,$ add$=4\text{'}$b$0111$;

initial begin

$//$ program

Memory $[10]=16\text{'}$h$3020$;

Memory $[11]=16\text{'}$h$7021$;

Memory $[12]=16\text{'}$hB$014$;

$//$ data at byte addres

Memory $[32]=16\text{'}$d$7$;

Memory $[33]=16\text{'}$d$5$;

$//$set the program counter to the start of

PC $=10$; state $=0$;

end

always @$($posedge clock$)$ begin

case $($state$)$

$0$: begin

MAR PC;

state$=1$;

end

$1$: begin $//$ fetch the instruction from mem

IR Memory$[$MAR$]$;

PC PC $+1$;

state$=2$; $//$next state

end

$2$: begin $//$Instruction decode

MAR IR$[11$:$0]$;

state$=3$;

end

$3$: begin $//$ Operand fetch

state$=4$;

case $($IR$[15$:$12])$

load : MBR Memory$[$MAR$]$ ;

add : MBR Memory$[$MAR$]$ ;

store: MBRAC;

endcase

end

$4$: begin $//$execute

if $($IR$[15$:$12]==4\text{'}$h$7)$ begin

AC AC$+$MBR;

state $=0$;

end

else if $($IR $[15$:$12]==4\text{'}$h$3)$ begin

AC MBR;

state $=0$; $//$ next state

end

else if $($IR$[15$:$12]==4\text{'}$hB$)$ begin

Memory$[$ MAR MBR;

state $=0$;

end

end

endcase

end

endmodule