Question: Since there is no point for whichg(x)does not exist, x =1 is the only critical number. Thus, the number line can be divided into two

Since there is no point for whichg(x)does not exist, x =1 is the only critical number. Thus, the number line can be divided into two intervals (,1) and (1, ). Determine the sign ofg(x)at one test value in each of the two intervals.First consider the interval (,1). Let x =0.g(x)=2(x 1)g(0)=21g(0)=2g(0)=

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