A small object with mass 4.05 kg moves counterclockwise with constant angular speed 1.70rad/s in a circle of radius 3.35 m entered at the origin. It starts at the point with position vector 3.35m. Then it undergoes an angular displacement of 8.95 rad. 

(a) What is its new position vector? 

 (b) In what quadrant is the object located and what angle does its position vector make with the positive x-axis? 

 (c) What is its velocity? 

 (d) In what direction is it moving? (Give a negative angle.)

 (e) What is its acceleration? m/s2

 (f) What total force is exerted on the object? 

Answer rating: 100% (QA)

a What is its new position vector The position vector of the object can be calculated using the following formula x r costheta y r sintheta where r is ... View the full answer