Question: So f is the function defined on I = par f ( x ) = x + 1 x - . Then f is strictly

So f is the function defined on I= par f(x)=x+1x-. Then
f is strictly increasing on .
f is strictly decreasing on I=|1;+|~.
f isn't monotonic on .
So f is the function defined on I = par f ( x ) =

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