Question: so is the final answer: Let ( x ) be an arbitrary element of ( (A cup C) setminus B ). This means that (

so is the final answer: Let ( x ) be an arbitrary element of ( (A \cup C) \setminus B ). This means that ( x ) is in ( A \cup C ) and not in ( B ). If ( x ) is in ( A ), then since ( x ) is not in ( B ), ( x ) is in ( A \setminus B ). If ( x ) is in ( C ), then since ( x ) is not in ( B

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