Solution: D

$tan40=\frac{\text{H}\text{e}\text{i}\text{g}\text{h}\text{t}}{30(m)}$

Height $=30tan40=25\mathrm{.}2m$

Problem $9\mathrm{.}6$

Which of the following statements is false?

A$.$ With $0$ to $90$ degree azimuth, your bearing $=0$ to $90$ degree bearing

B$.$ With $90$ to $180$ degree azimuth, your bearing $=180-$azimuth

C$.$ With $180$ to $270$ degree azimuth, your bearing $=$ azimuth $-180$

D$.$ With $270$ to $360$ degree azimuth, your bearing $=360-$azimuth

E$.$ None of the above