Solution format:

Given 91 = 6. 6 x10 # C - 92 = 3.0 X 10 UC - r = Q.930 m - Fe = ? F = kqiqz r2 - = 9.0 x 109 N. m2//2 (6. 0 x 10-"() (3.0 x10 " x ) ( 9 . 030 m ) 2 = 9. 162 1.m/X 9.0 x 10 - 4 my ? = 180 N 11 * Repulsive Force\fACTIVITY: Electrostatic Series Using the data below, identify what happens to objects when they rub against each other. gold hold e- tight sulfur brass copper rubber wax silk lead for wool glass acetate lose e- easily Example: 0 A rubber is rubbed with fur, electrons are transferred from the for to the plastic: plastic becomes - and for + Materials in Contact Positively Negatively Charged Charged gold and silk Wool and glass Sulfur and acetate Lead and copper Wax and acetate Problem Solving: Solve the problem below. Show your solution. 1. Two protons in an atom are 1.75 m x 10 1'3 m from each other. Calculate the electric force between them. 2. Calculate the magnitude of the electrostatic force between a + 6.0pC charged particle and a + 8.0LJC charged particle separated by a distance of 0.7 cm. 3. Two charges attract each other with a force of 90 N. How far a 5.0 x l()-*5 C charge from o -3.0 x 10 -5 C charge