Question: Solution steps please 5. Fig. 1 below shows an arrangement of four charged particles, with angle 0 = 30.0 and distance d - 2.00 cm.

Solution steps please

5. Fig. 1 below shows an arrangement of four charged particles, with angle 0 = 30.0 and distance d - 2.00 cm. Particle 2 has charge 92 = +8.00 x 10"" C; particles 3 and 4 have charges q3 = q4 = - 1.60 x 10-19 C. (a) What is distance D between the origin and particle 2 if the net electrostatic force on particle 1 due to the other particles is zero? [Ans: 1.92 cm] (b) If particles 3 and 4 were moved closer to the x axis but maintained their symmetry about that axis, would the required value of D be greater than, less than, or the same as in part (a)? [Ans: decreased] F13 +8 x 10 19 D 2 16 X 10-19 Fig. 1

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