Question: Solution to the equation e-1 = 5 is %3D Select one: Oaz= 2kn +1-i ln5 Ob. z =-2kn +1 +i ln 5 Ocz= 2kn

Solution to the equation e-1 = 5 is %3D Select one: Oaz= 2kn +1-i ln5 Ob. z =-2kn +1 +i ln 5 Ocz= 2kn +1+i ln 5 d. z= kn +1+iln5
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