Solve (8x + 5y)dx + (5x + 20y)dy = 0 Follow the step-by-step instruction below to learn to solve the exact differential equation. Suppose P(x, y) = (8x + 5y) and Q(x, y) = (5x + 20y) P(x, y)dx + Q(x, y)dy = 0 is exact on Rif Py(x, y) = Qz(x, y) Pz(x, y) = Qy(x, y) Py(x, y) = Qy(x, y) Pz(x, y) = Q(x, y) Therefore, the Exactness Theorem implies that there's a function F such that F(x, y) = P(x, y) and Fy = Q(x, y). Thus F(x, y) = P(x, y)d Meaning we integrate 8x + 5y with respect to x to obtain our first glimpse of the potential function. F(x, y) = 4r + 5ay + [ We now differentitate F(x, y) = to obtain 4x + 5xy + h(y) with respect to [