Solve

A uniform electric field # = 360 N/C points in the +-direction. A positive charge Q = +0.56 C is moved along different paths around a pair of isosceles right triangles with side lengths ab = db = ch = 6.6 cm. The triangle with vertices a, b, and lies in the lower half, with q to the left, to the right, and 6 between them along the base. Point d lies directly above 6, forming another isosceles right triangle with vertices d, b, and a. The electric field consists of evenly spaced lines pointing to the right, consistent with the positive x-direction. A coordinate system is shown with +z pointing right and +-y pointing upward. q E ry 7 \\ wo ' ', +y oe too +X a b Cc |. x 1) When the charge is moved from point a to point c along a straight path (through point b), what happens to the electrical potential energy of the charge Q? The potential energy increases. The potential energy decreases. The potential energy remains the same