Question: solve error function ( expr , width.cutoff = 6 0 L , backtick = mode ( expr ) % in % c ( call

solve error function (expr, width.cutoff =60L, backtick = mode(expr)%in%
c("call", "expression", "(", "function"), control = c("keepNA",
"keepInteger", "niceNames", "showAttributes"), nlines =-1L)
.Internal(deparse(expr, width.cutoff, backtick, .deparseOpts(control),
nlines))
code:
library(methods)
randomVariate <- function(distFormula, defs){
# Constructor method
obj <- function(n){
# Function to evaluate the formula and sample from distributions
eval(distFormula, defs, parent.frame()) # Evaluate the formula with provided definitions
}
# Set class
class(obj)<- c("randomVariate", class(obj))
return(obj)
}
# Define print method for "randomVariate" objects
setMethod("show", "randomVariate", function(object){
cat("Formula:", deparse(object@distFormula),"
")
cat("Definitions:
")
for (key in names(object@defs)){
cat(key,"---", deparse(object@defs[[key]]),"
")
}
})
# Example usage
set.seed(123) # for reproducibility
# Define a new random variable
newDist <- randomVariate(
distFormula = ~x^2,
defs = list(x = function(n) rnorm(n))
)
# Print the object
print(newDist)
# Generate a random sample
sample1<- newDist(10^5)
# Plot a histogram of the sample
hist(sample1, breaks = "Scott", probability = TRUE, col = rgb(1,0,1,2), density =20, angle =45)
lines(density(sample1, adjust =5), col = rgb(1,0,1,1))

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