Question: Solve Find the solution to the differential equation d's y + 4. day 1 . dy dt 3 dt 2 dt - 4y = 0;

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Find the solution to the differential equation d's y + 4. day 1 . dy dt 3 dt 2 dt - 4y = 0; y(0) = 1 y'(0) =0 y"(0) =0 Hint: One root of the characteristic polynomial is 1 y(t) = symbolic expression

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