Solve for the slope correction if:

$150\mathrm{.}50$Feet$=$slope distance

$29\mathrm{.}70$Feet$=$vertical distance.

$0\mathrm{.}022$#$/$FT$=$weight of tape per foot

$65\mathrm{.}12$Feet$=$unsupported length of tape

$10\mathrm{.}00$#$=$pull applied to tape.