Solve for $y$ if $\frac{dy}{dx}=(xy{)}^2$ and $y(0)=1.$

$(1$ point$)$

$y=\frac{-3}{x^3-3}$

$y=\frac{-3}{x^{3}1}$

$y=\frac{9}{x^{3}2}$

$y=\frac{-9}{x^{3}2}$

$y=\frac{-2}{x^3-2}$