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Heating solid sodium bicarbonate in a closed vessel established this equilibrium: 2NaHCO,(s) = Na,CO,(s) + H,O(g) + CO, (g) What would happen to the equilibrium position in the following situations (the temperature remains constant)? Part 1 of 3 Some of the H,0 was removed from the system. shift equilibrium to the right have no effect zz Ls shift equilibrium to the left Part 2 of 3 Some of the solid NaHCO, was removed from the system. shift equilibrium to the right | | have no effect shift equilibrium to the left Part 3 of 3 Some of the solid Na,CO, was removed from the system. shift equilibrium to the right | | have no effect shift equilibrium to the left