Question: SOLVE IN PYTHON! f ( x ) = x ^ cos ( x ^ 2 ) , integral from 0 to 4 ( f (

SOLVE IN PYTHON!
f(x)= x^cos(x^2), integral from 0 to 4(f(x)dx)
Recall the left endpoint rule (example illustrated below):
abg(x)dx~~i=1ng(xi-1)x
where xi=a+i*x and x=1n(b-a).
Follow the steps below. Only parts (c) and (d) require
printed output in your submitted work.
(a) Define a Python function that accepts an ordered pair (representing an interval) as its input and returns the numerical result of applying the left endpoint rule to f(x) on that interval.
(b) Use the function you wrote in part (a) to define a new Python list that contains the results of applying the left endpoint rule to f(x) on each subinterval in Partition.
(c) Sum the list from part (b) to obtain an approximation for the area under f(x) on [0,4].Print your output without rounding. The result should be 4.03535533686618 if you have set up your approximation correctly.
(d) The true value of integral from 0 to 4(f(x)dx) to 15 decimal places is 4.046085774496901. Use this value to print an estimate for the error =|actual approximation|.
 SOLVE IN PYTHON! f(x)= x^cos(x^2), integral from 0 to 4(f(x)dx) Recall

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