Solve the Differential equation in changes in temperature i have all the details on excel please solve the DE mode in blue the other data should help you.

T (F) t (min) AT At AT/At 40 0 0.327917281 Changes in Temperature During a Freeze-Thaw Cycle Temperature During a Freeze-Thaw Cycle 15 -3.7349E-05 IT/dt=-Cos(t*PI()/4.42)*SIN(t*PI()*0.5)-0.2*EXP(t/20)/(t*800-1) 45 30 -0.333333333 0.842700778 1.5 40 45 0.2 -8.36915E-05 60 0.266666667 0.995194956 30 75 -0.2 -0.000250051 30 90 0.333333333 -0.720012939 0.5 105 0.333333333 -0.000840485 25 120 -0.2 -0.136217337 Temperature (T Change in Temperature (AT) 135 N W y co i co un t w w in in is A d in a 0.2 -0.003013429 20 :190 200 250 300 150 -0.266666667 0.502385184 15 165 0.333333333 -0.011254361 -0 180 0.533333333 0.910479487 10 195 8 -0.043232999 -1 28 210 0.533333333 0.870349505 35 225 0.466666667 -0.169537124 O -15 38 0 240 200 0.2 -0.425399538 Time (t) 50 100 150 250 40 260 0.1 (minutes) Time (t) (minutes) Table 1: Temperature Readings over the Time of a Single Freeze-Thaw Cycle Figure 1: Change in Temperature over Time Figure 2: Temperature over Time Dependent Variable T Temperature ('F) Independent Variable t Time (min) AT Change in Temperature = T2 - T1 Differential Equation Model is: Change in Time = t2 - t1 di dt =-COS(t* PI()/4.42)*SIN(t*PI()*0.5)-0.2*EXP(t/20)/(t*800-1) Table 2: Variable Definition Equation 1: Differential Equation Model\f