Question: Solve the equation. (x3 + 6x3 4 ) dx + ex y'dy = 0 An implicit solution in the form F(x,y) = C is =

Solve the equation. (x3 + 6x3 4 ) dx + ex y'dy = 0 An implicit solution in the form F(x,y) = C is = C, where C is an arbitrary constant. (Type an expression using x and y as the variables.)sol : - (x3 + 6 x 3 yu / dx + ex y3ly = 0 x3 ( 1+ by 4 ) obx + e " y 3 dy = 0 dividing both side by 73 43 , weget 1+ by oxy 4 3 23 dy = 0 1+64 dx 43 23 ly = > ox = - oxy Itbyy by put 24 = z and Itby " = u x3 ch = dz J dy = dy 24 = - dy 24 u = > glu Integrating both sides , we get e = = log u + C 6 => e 't t loqu = c . c = blog ( Itby 2) - exy

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