Question: Solve the following 2 recurrence relations using repeated substitution D(1)=3 D(2n)=D(n)+3 and G(1)=9 G(2n)=G(n)+6n+6

Solve the following 2 recurrence relations using repeated substitution

D(1)=3

D(2n)=D(n)+3

and

G(1)=9

G(2n)=G(n)+6n+6

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