Solve the following differential equation for the general solution:

$2x-y\frac{dy}{dx}=3$

Select one:

a$.x^2-y-3x$

b$.x^2-3x=\frac{1}{2}{y}^{2}C$

c$.\frac{1}{2}ln|2x-3|=ln|y|C$

d$.y=\sqrt[\phantom{2}]{2x^2-6x}C$