Question: solve the following exponential equations algebraically showing steps a. 9^5^x =(3)^3(27)^4x b. {2/3}^4x ={3/2}{27/8}^2x Thank you

solve the following exponential equations algebraically showing steps

a. 9^5^x =(3)^3(27)^4x

b. {2/3}^4x ={3/2}{27/8}^2x

Thank you

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